The coefficient of thermal expansion for volume is usually 3 times the coeficcient for expansion for length

To estimate the cube for a number between 1 and 1.1

Step 1

Subtract 1 from the number

Step 2

Multiply the quantity you calculated in step 1 by 3

Step 3

Add 1 to the number you calculated in step 2

Finished

@shortstories Funny how if three lengths increase by 1, the volume increases by 3

@Zergling_man

Only for numbers in the range that happens to be used for thermal expansion calculations for some materials near room temperature when the temperature change is small enough

I do not think it works for large numbers

The sine of theta in radians is also close to theta for angles smaller than a certain angle but not for angles larger than a certain angle

@Zergling_man

The volume is not three times the length

the change in volume is approximately three times the change in length

If the change in length is less than 10% the original length

@shortstories Somewhere around 1.75 the result of multiplying by three and cubing pass each other. I guess that doesn't hold when you're starting from non-zero but... ... If anything, it shrinks, and should shrink towards 0? So I don't think that's true for all lengths.

@Zergling_man

I would not know how to use the method to calculate cubes for numbers above 4/3 because 3*4/3=2

And I am looking at the digits after 1 when you cube a number above 1 written as a decimal

Follow

@Zergling_man

1.3333333333333333^3

is approxinstely equal to

1.9999999999999999^3

according to the drecribed estimation technique

(4/3)^3 is approximately equal to 2

3"((4/3)-1)+1 = 2

You are multiplying the digits after 1 by 3 and keeping the ones digit the same for numbers greater than or equal to 1 and less than or equal to 4/3

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@Zergling_man

You can do the same thing for bigger numbers by sutracting 1 then mu!tiplying the number by 3 then adding 1 in that order

(1.75-1)*3+1 =3.25

1.75^3=5.359 rounded

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